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easy +10 pts

Anagram check

Sorted signatures or Counter maps.

Implement `is_anagram(a: str, b: str) -> bool`. Ignore case; only consider alphabetical characters.

Constraints

0 ≤ len(s) ≤ 10^4

Example

>>> is_anagram("listen", "silent")
True
10 points ~10 min

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Hints

Sort both strings or use collections.Counter.
Python 3
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