Implement `rle_compress(s: str) -> str`.
Compress runs: each group of consecutive identical chars becomes `char + count`.
If the compressed string is not shorter, return the original.
Constraints
0 ≤ len(s) ≤ 10^5; only lowercase letters
Example
>>> rle_compress("aaabbc")
"a3b2c1"
20 points
~20 min
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Scan with a running count; append char+count when char changes.
Python 3
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